最长子序列回文问题，Longest Palindromic Subsequence

Given a string s, find the longest palindromic subsequence's length in s. You may assume that the maximum length of s is 1000.

Example 1:
Input:

"bbbab"

Output:

4

One possible longest palindromic subsequence is "bbbb".

Example 2:
Input:

"cbbd"

Output:

2

One possible longest palindromic subsequence is "bb". 

public class longestsubPalindrome {public static int longsubPalin(String s) {  //求最长回文子序列长度char[] ch = s.toCharArray();int[][] dp = new int[ch.length][ch.length];for (int i = 0; i < ch.length; i++) {dp[i][i] = 1;}for (int i = 1; i < ch.length; i++) {for (int j = i - 1; j >= 0; j--) {if (ch[i] == ch[j])dp[j][i] = dp[j + 1][i - 1] + 2;else {dp[j][i] = Math.max(dp[j + 1][i], dp[j][i - 1]);}}}return dp[0][ch.length - 1];}public static String subPalin(String s) { //求最长子序列对应长度的字符串char[] ch = s.toCharArray();String[][] dp = new String[ch.length][ch.length];for(int i=0;i<ch.length;i++){for(int j=0;j<ch.length;j++){dp[i][j]="";}}for (int i = 0; i < ch.length; i++) {dp[i][i] = dp[i][i]+ch[i];}for (int i = 1; i < ch.length; i++) {for (int j = i - 1; j >= 0; j--) {if (ch[i] == ch[j]) {dp[j][i] = dp[j + 1][i - 1]+ch[j];dp[j][i]=ch[j]+dp[j][i];} else {dp[j][i] = dp[j + 1][i].length()>dp[j][i - 1].length()?dp[j + 1][i]:dp[j][i - 1];}}}return dp[0][ch.length - 1].toString();}public static void main(String[] args) {System.out.println(longsubPalin("cbbd"));System.out.println(subPalin("cbbd"));System.out.println(longsubPalin("bbabb"));System.out.println(subPalin("bbabb"));}}