Keyboard Row

#include <stdio.h>#include <string.h>//字符串1是否包含字符串2,在同一行int inStr(char *str1, char *str2){    int i, j, str1len = strlen(str1), str2len = strlen(str2);    int flag = str2len;    int temp;    for (i = 0; i < str2len; i++)    {        for (j = 0; j < str1len; j++)        {            temp = abs(str2[i] - str1[j]);            if ((str2[i] == str1[j]) || temp==32)            {                flag--;                break;            }        }    }    if (flag == 0) return 1;    else return 0;}char** findWords(char** words, int wordsSize, int* returnSize) {    char* keyBoardStr[] = { "qwertyuiop","asdfghjkl","zxcvbnm" };    char** result = (char**)malloc(wordsSize*sizeof(char*));    int i,flag;    if (words == NULL)        return NULL;    for (i = 0; i<wordsSize; i++)        result[i] = (char*)malloc(100 * sizeof(char));    for (i = 0; i < wordsSize; i++)    {        if (inStr(keyBoardStr[0], words[i]))            flag = 1;        else if (inStr(keyBoardStr[1], words[i]))            flag = 1;        else if (inStr(keyBoardStr[2], words[i]))            flag = 1;        if (flag == 1)        {            result[*returnSize] = words[i];            *returnSize += 1;        }        flag = 0;    }    return result;}void  main() {    char* input[4] = { "Hello", "Alaska", "Dad", "Peace" };    char** result = (char**)malloc(4 * sizeof(char*));    int len=0;    result = findWords(input,4,&len);    printf("%s\n", result[0]);    printf("%s\n", result[1]);    printf("%d\n", len);    system("pause");}