a letter and a number
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- 输入
- On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).
- 输出
- for each case, you should the result of y+f(x) on a line
- 样例输入
6R 1P 2G 3r 1p 2g 3
- 样例输出
191810-17-14-4
#include<stdio.h>int main(){ int x,n;scanf("%d",&x);while(x--){getchar();
char c;scanf("%c %d",&c,&n);if(c>=65&&c<=90) c=c-64;else c=0-(c-96);n=c+n;printf("%d\n",n); }}
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