a letter and a number
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a letter and a number
时间限制:3000 ms | 内存限制:65535 KB
难度:1
- 描述
- we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).- 输入
- On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).
- 输出
- for each case, you should the result of y+f(x) on a line
- 样例输入
6R 1P 2G 3r 1p 2g 3
- 样例输出
191810-17-14-4
查看代码---运行号:252173----结果:Accepted
运行时间:2012-10-05 11:36:47 | 运行人:huangyibiao
01.
#include <iostream>
02.
using
namespace
std;
03.
04.
int
main()
05.
{
06.
int
testNum;
07.
cin >> testNum;
08.
char
letterX;
09.
int
numY;
10.
while
(testNum--)
11.
{
12.
cin >> letterX >> numY;
13.
if
(letterX -
'a'
>= 0)
//小写
14.
{
15.
cout << numY - (letterX -
'a'
) - 1 << endl;//别忘了-1
16.
}
17.
else
18.
cout << numY + (letterX -
'A'
) + 1 << endl;//别忘了加1
19.
}
20.
return
0;
21.
}
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