南阳理工：a letter and a number

a letter and a number
时间限制：3000 ms  |  内存限制：65535 KB
难度：1

描述

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

输入

On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).

输出

for each case, you should the result of y+f(x) on a line

样例输入

6  R 1  P 2  G 3  r 1  p 2  g 3

样例输出

19  18  10  -17  -14  -4

#include<stdio.h>
int main()
{
 int N,a;
 char ch,c;
 scanf("%d",&N);
 while(N--)
 {
  c=getchar();
  scanf("%c %d",&ch,&a);
  if(ch>='A'&&ch<='Z')
   printf("%d\n",ch-'A'+1+a);
  else if(ch>='a'&&ch<='z')
   printf("%d\n",'a'-ch-1+a);
 }
 return 0;
}