tensorflow报错:Shape must be rank 2 but is rank 3 for 'MatMul' (op: 'MatMul')
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tensorflow矩阵相乘,秩不同报错
在tensorflow中写了这样一句:
- y_out = tf.matmul(outputs, W)
y_out = tf.matmul(outputs, W)
其中,outputs的shape为[16,336,400],W的shape为[400,1]
出现以下报错:
Shape must be rank 2 but is rank 3 for ‘MatMul’ (op: ‘MatMul’) with input shapes: [16,336,400], [400,1].
Numpy下同样的写法没有问题
- import numpy as np
- A = np.array([[[1, 2, 3, 4],
- [5, 6, 7, 8],
- [9, 0, 1, 2]],
- [[4, 3, 2, 1],
- [8, 7, 6, 5],
- [2, 1, 0, 9]]])
- print(A)
- print(A.shape)
- print(‘—————————’)
- B = np.array([[1], [2], [3], [4]])
- print(B)
- print(B.shape)
- print(‘—————————’)
- C = np.matmul(A, B)
- print(C)
- print(C.shape)
import numpy as npA = np.array([[[1, 2, 3, 4], [5, 6, 7, 8], [9, 0, 1, 2]], [[4, 3, 2, 1], [8, 7, 6, 5], [2, 1, 0, 9]]])print(A)print(A.shape)print('---------------------------')B = np.array([[1], [2], [3], [4]])print(B)print(B.shape)print('---------------------------')C = np.matmul(A, B)print(C)print(C.shape)
输出结果:
- [[[1 2 3 4]
- [5 6 7 8]
- [9 0 1 2]]
- [[4 3 2 1]
- [8 7 6 5]
- [2 1 0 9]]]
- (2, 3, 4)
- —————————
- [[1]
- [2]
- [3]
- [4]]
- (4, 1)
- —————————
- [[[30]
- [70]
- [20]]
- [[20]
- [60]
- [40]]]
- (2, 3, 1)
[[[1 2 3 4] [5 6 7 8] [9 0 1 2]] [[4 3 2 1] [8 7 6 5] [2 1 0 9]]]
解决办法
- import numpy as np
- import tensorflow as tf
- sess = tf.Session()
- A = np.array([[[1, 2, 3, 4],
- [5, 6, 7, 8],
- [9, 0, 1, 2]],
- [[4, 3, 2, 1],
- [8, 7, 6, 5],
- [2, 1, 0, 9]]])
- B = np.array([[1], [2], [3], [4]])
- A = tf.cast(tf.convert_to_tensor(A), tf.int32) # shape=[2, 3, 4]
- B = tf.cast(tf.convert_to_tensor(B), tf.int32) # shape=[4, 1]
- #—————————————–修改部分(开始)—————————————–
- #要想让A和B进行tf.matmul操作,第一个维数必须一致。因此要把B先tile后转成[2, 4, 1]维
- B_ = tf.tile(B, [2, 1])# B的第一维复制2倍,第二维复制1倍
- B = tf.reshape(B_, [2, 4, 1])
- # 或 更通用的改法:
- #B_ = tf.tile(B, [tf.shape(A)[0], 1])
- #B = tf.reshape(B_, [tf.shape(A)[0], tf.shape(B)[0], tf.shape(B)[1]])
- #—————————————–修改部分(结束)—————————————–
- #此时就可以matmul了
- C = tf.matmul(A, B)
- print(‘C:’,C.get_shape().as_list())
- sess.run(C)
import numpy as npimport tensorflow as tfsess = tf.Session()A = np.array([[[1, 2, 3, 4], [5, 6, 7, 8], [9, 0, 1, 2]], [[4, 3, 2, 1], [8, 7, 6, 5], [2, 1, 0, 9]]])B = np.array([[1], [2], [3], [4]])A = tf.cast(tf.convert_to_tensor(A), tf.int32) # shape=[2, 3, 4]B = tf.cast(tf.convert_to_tensor(B), tf.int32) # shape=[4, 1]#-----------------------------------------修改部分(开始)-----------------------------------------#要想让A和B进行tf.matmul操作,第一个维数必须一致。因此要把B先tile后转成[2, 4, 1]维B_ = tf.tile(B, [2, 1])# B的第一维复制2倍,第二维复制1倍B = tf.reshape(B_, [2, 4, 1])# 或 更通用的改法:#B_ = tf.tile(B, [tf.shape(A)[0], 1])#B = tf.reshape(B_, [tf.shape(A)[0], tf.shape(B)[0], tf.shape(B)[1]])#-----------------------------------------修改部分(结束)-----------------------------------------#此时就可以matmul了C = tf.matmul(A, B)print(‘C:’,C.get_shape().as_list())sess.run(C)
输出结果:
- (‘C:’, [2, 3, 1])
- array([[[30],
- [70],
- [20]],
- [[20],
- [60],
- [40]]], dtype=int32)
('C:', [2, 3, 1])array([[[30], [70], [20]], [[20], [60], [40]]], dtype=int32)
转自博客:http://blog.csdn.net/blythe0107/article/details/74171870
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