1481:Maximum sum
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describe
Given a set of n integers: A={a1, a2,…, an}, we define a function d(A) as below:
t1 t2 d(A) = max{ ∑ai + ∑aj | 1 <= s1 <= t1 < s2 <= t2 <= n } i=s1 j=s2
1
2
3
1
2
3
Your task is to calculate d(A).
input
The input consists of T(<=30) test cases. The number of test cases (T) is given in the first line of the input.
Each test case contains two lines. The first line is an integer n(2<=n<=50000). The second line contains n integers: a1, a2, …, an. (|ai| <= 10000).There is an empty line after each case.
output
Print exactly one line for each test case. The line should contain the integer d(A).
sample input
1
10
1 -1 2 2 3 -3 4 -4 5 -5
1
2
3
4
1
2
3
4
sample output
13
1
1
Prompt
In the sample, we choose {2,2,3,-3,4} and {5}, then we can get the answer.
Huge input,scanf is recommended.
这题用两遍dp从左到右算一次,再从右到左算一次。
#include<bits/stdc++.h>using namespace std;int t,n,a[100001],s[100001],r[100001],i,j,minn=-999999,r1[100001];int main(){ cin>>t; while(t--) { cin>>n; memset(r1,0,sizeof(r1)),memset(a,0,sizeof(a)),memset(s,0,sizeof(s)),memset(r,0,sizeof(r)),minn=-9999999; for(i=1;i<=n;i++) cin>>a[i]; s[1]=a[1],r[n]=a[n]; for(i=2;i<=n;i++) s[i]=max(s[i-1]+a[i],a[i]); for(i=n-1;i>=1;i--) r[i]=max(r[i+1]+a[i],a[i]); r1[n]=r[n]; for(i=n-1;i>=1;i--) r1[i]=max(r1[i+1],r[i]); for(i=2;i<=n;i++) minn=max(minn,s[i-1]+r1[i]); cout<<minn<<endl; } return 0;}
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