PAT basic 1017

来源:互联网 发布:烈焰传奇翅膀进阶数据 编辑:程序博客网 时间:2024/05/29 03:20
#include <iostream>#include <string>using namespace std;int main() {    string s;    cin >> s;    int a;    cin >> a;    int len = s.length();    int t = 0;    int temp = 0;    t = (s[0] - '0') / a;    if ((t != 0 && len > 1) || len == 1) {   //这边还是挺棒的啊         cout << t;    }    temp = (s[0] - '0') % a;    for (int i = 1; i < len; i++) {        t = (temp * 10 + s[i] - '0') / a;        cout << t;        temp = (temp * 10 + s[i] - '0') % a;    }    cout << " " << temp;    return 0;}
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