Java如何获取当前的jar包路径

public LatticeAlgorithm(BinaryRelation bRel,RelationalContextEditor rce){projectPath=this.getPath();//双击 && 右键打开方式Java...if(projectPath.equals(""))//cmd窗口： java -jar *.jarprojectPath=System.getProperty("user.dir");String javaProject=System.getProperty("user.dir");//下面是javaproject和jar可执行文件的区别if(LatticeAlgorithm.class.getResource("LatticeAlgorithm.class").toString().startsWith("file"))projectPath=javaProject;//java工程中执行binRel = bRel;this.rce=rce;lattice = new CompleteConceptLatticeImp();}private String getPath(){String filePath = System.getProperty("java.class.path");String pathSplit = System.getProperty("path.separator");// windows下是";",linux下是":"if (filePath.contains(pathSplit)){filePath = filePath.substring(0, filePath.indexOf(pathSplit));} else if (filePath.endsWith(".jar")){// 截取路径中的jar包名,可执行jar包运行的结果里包含".jar"// 此时的路径是"E:\workspace\Demorun\Demorun_fat.jar"，用"/"分割不行// 下面的语句输出是-1，应该改为lastIndexOf("\\")或者lastIndexOf(File.separator)// System.out.println("getPath2:"+filePath.lastIndexOf("/"));filePath = filePath.substring(0, filePath.lastIndexOf(File.separator) + 1);}return filePath;}