PAT basic 1029
来源:互联网 发布:linux 终端切换 编辑:程序博客网 时间:2024/06/07 05:48
#include <iostream>#include <cctype>using namespace std;int main() { string a, b; cin >> a >> b; char c[80]; int flag, index = 0; for (int i = 0; i < a.length(); i++) { flag = 0; for (int j = 0; j < b.length(); j++) { if (a[i] == b[j]) { flag = 1; break; } } if (!flag) c[index++] = toupper(a[i]); } for (int i = 1; i < index; i++) { //去掉重复的字符 for (int j = 0; j < i; j++) { if (c[i] == c[j]) { c[i] = '#'; break; } } } for (int i = 0; i < index; i++) if (c[i] != '#') cout << c[i]; return 0;}
阅读全文
0 0
- PAT basic 1029
- PAT Basic 1029
- pat-basic-1029-c语言
- PAT Basic
- Pat(Basic Level)Practice--1029(旧键盘)
- PAT乙级(Basic Level)1029(C++)
- PAT(basic level) 1029 旧键盘(20)
- PAT (Basic Level) Practise
- PAT Basic 1001
- PAT Basic 1002
- PAT Basic 1005
- PAT Basic 1006
- PAT Basic 1007
- PAT Basic 1008
- PAT Basic 1009
- PAT Basic 1010
- pat basic level 1016
- pat basic level 1018
- 熟悉STL顺序容器的使用之vector
- PAT basic 1028
- JAVA语言(五)
- eclipse找不到tools.jar下的内容的解决方法
- maven 介绍
- PAT basic 1029
- PAT basic 1030
- 机器学习集训营---第四周总结
- Java菜鸟教程 一些简单的练习
- Educational Codeforces Round 26 C. Two Seals
- 瞬时态、持久态、脱管态
- python 學習的一些心得分享(基礎)
- Java 异常总结
- Unity3D