453. Minimum Moves to Equal Array Elements DescriptionHintsSubmissionsDiscussSolution Discuss Pick O

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453. Minimum Moves to Equal Array Elements

DescriptionHintsSubmissionsDiscussSolution
DiscussPick One

Given a non-empty integer array of size n, find the minimum number of moves required to make all array elements equal, where a move is incrementing n - 1 elements by 1.

Example:

Input:[1,2,3]Output:3Explanation:Only three moves are needed (remember each move increments two elements):[1,2,3]  =>  [2,3,3]  =>  [3,4,3]  =>  [4,4,4]


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题意:

给你一个有n个数的数组。每次给n-1个数加一,直到所有的数相等,求这个最小的步数

算法思路:

为了求最小的步数,所以每次肯定是给除了最大的那个数+1,这就相当于每次给最大的数-1,直到大家都和最小的数相等
所以遍历数组中的元素,求出来最小值,然后数组中每个数和最小值之间的差值的和就是最短的步数

代码:

package easy;public class MinimumMovestoEqualArrayElements {public int minMoves(int[] nums) {        int min = nums[0];        int sum = 0;        for(int i=0; i<nums.length; i++){        if(nums[i] < min){        min = nums[i];        }        sum += nums[i];        }                return sum - min*nums.length;    }}


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