[py]tornado-jquery ajax

来源：互联网发布：大数据平台对比分析编辑：程序博客网时间：2024/05/22 16:03

通过jquery发请求

Jquery ajax登录-从表单获取数据

完整code

#!/usr/bin/env python# coding=utf-8import timeimport tornado.ioloopimport tornado.web# 业务逻辑处理模块class LoginHandler(tornado.web.RequestHandler):    def post(self, *args, **kwargs):        dic = {"status":True,"message":""}        username = self.get_argument("username")        password = self.get_argument("password")        if username=="admin" and password=="admin123":            pass        else:            dic["status"] = False            dic["message"]="用户名或密码错误"        import json        self.write(json.dumps(dic))    def get(self, *args, **kwargs):        self.render("login.html")# 配置选项模块settings = {    'template_path': 'template',    'static_path': 'statics',}# 路由模块application = tornado.web.Application([    (r"/login", LoginHandler),],    **settings)## wsgi模块if __name__ == "__main__":    application.listen(8888)    tornado.ioloop.IOLoop.instance().start()

<!doctype html><html lang="en"><head>    <meta charset="UTF-8">    <meta name="viewport"          content="width=device-width, user-scalable=no, initial-scale=1.0, maximum-scale=1.0, minimum-scale=1.0">    <meta http-equiv="X-UA-Compatible" content="ie=edge">    <title>login</title>    <link rel="stylesheet" href="{{ static_url("common.css") }}"></head><body><form action="/login" method="post">    <input id="username" type="text" name="username">    <input id="password" type="password" name="password">    <input id="submit" type="button" value="登录" onclick="SubmitForm();"/></form><script src="{{static_url("jquery-1.8.3.min.js")}}"></script><script>    function SubmitForm() {        $.post('/login',{"username":$("#username").val(),"password":$("#password").val()},function (callback) {            console.log(callback);        })    }</script></body></html>

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