Triangles FZU
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题目大意:
给你两个三角形,判断他们的关系:包含,相交,相离
代码:
#include <iostream>#include <cmath>#include <cstdio>#define ABS_FLOAT_0 0.0001using namespace std;struct Point{ double x,y;};struct Triangle{ Point A,B,C;};//ab和ac两向量叉积double mult(Point a,Point b,Point c){ return (a.x-c.x)*(b.y-c.y)-(b.x-c.x)*(a.y-c.y);}//aa, bb为一条线段两端点 cc, dd为另一条线段的两端点 相交返回true, 不相交返回falsebool intersect(Point aa, Point bb, Point cc, Point dd){ if ( max(aa.x, bb.x)<min(cc.x, dd.x) ) return false; if ( max(aa.y, bb.y)<min(cc.y, dd.y) ) return false; if ( max(cc.x, dd.x)<min(aa.x, bb.x) ) return false; if ( max(cc.y, dd.y)<min(aa.y, bb.y) ) return false; if ( mult(cc, bb, aa)*mult(bb, dd, aa)<0 ) return false; if ( mult(aa, dd, cc)*mult(dd, bb, cc)<0 ) return false; return true;}//求三角形面积double Get_Triangle_Squar(Point A,Point B,Point C){ return fabs(mult(A,B,C))/2.0;}//判断点D是否在三角形ABC内bool IsInTriangle(const Point A, const Point B, const Point C, const Point D){ double SABC, SADB, SBDC, SADC; SABC = Get_Triangle_Squar(A, B, C); SADB = Get_Triangle_Squar(A, D, B); SBDC = Get_Triangle_Squar(B, D, C); SADC = Get_Triangle_Squar(A, D, C); double SumSuqar = SADB + SBDC + SADC; if ((-ABS_FLOAT_0 < (SABC - SumSuqar)) && ((SABC - SumSuqar) < ABS_FLOAT_0)) return true; else return false;}int main(){ int T; scanf("%d",&T); while(T--) { Triangle a,b; scanf("%lf%lf%lf%lf%lf%lf",&a.A.x,&a.A.y,&a.B.x,&a.B.y,&a.C.x,&a.C.y); scanf("%lf%lf%lf%lf%lf%lf",&b.A.x,&b.A.y,&b.B.x,&b.B.y,&b.C.x,&b.C.y); if(IsInTriangle(a.A,a.B,a.C,b.A)&&IsInTriangle(a.A,a.B,a.C,b.B)&&IsInTriangle(a.A,a.B,a.C,b.C)) { printf("contain\n"); } else if(IsInTriangle(b.A,b.B,b.C,a.A)&&IsInTriangle(b.A,b.B,b.C,a.B)&&IsInTriangle(b.A,b.B,b.C,a.C)) { printf("contain\n"); } else if(intersect(a.A,a.B,b.A,b.B)||intersect(a.A,a.B,b.A,b.C)||intersect(a.A,a.B,b.B,b.C)) { printf("intersect\n"); } else if(intersect(a.A,a.C,b.A,b.B)||intersect(a.A,a.C,b.A,b.C)||intersect(a.A,a.C,b.B,b.C)) { printf("intersect\n"); } else if(intersect(a.B,a.C,b.A,b.B)||intersect(a.B,a.C,b.A,b.C)||intersect(a.B,a.C,b.B,b.C)) { printf("intersect\n"); } else { printf("disjoint\n"); } } return 0;}
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