hdu1012 u Calculate e
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Problem Description
A simple mathematical formula for e is
where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
Output
Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.
Sample Output
n e- -----------0 11 22 2.53 2.6666666674 2.708333333
Source
Greater New York 2000
#include<stdio.h>int main(){ double e=1; int i,t=1; printf("n e\n- -----------\n0 1\n"); for(i=1;i<10;i++) { t=t*i; e=e+1.0/(double)t; if(i>=3) printf("%d %.9lf\n",i,e); else if(i==2) printf("%d %.1lf\n",i,e); else printf("%d %.0lf\n",i,e); } return 0;}Iterative Method
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