南阳OJ-题目217：a letter and a number

题目描术：

a letter and a number

时间限制：3000 ms  |  内存限制：65535 KB

难度：1

描述

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

输入

On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).

输出

for each case, you should the result of y+f(x) on a line

样例输入

6R 1P 2G 3r 1p 2g 3

样例输出

191810-17-14-4

2.运行代码

import java.io.BufferedReader;import java.io.IOException;import java.io.InputStreamReader;/* * Dragon 2017.8.31 * a letter and a number */public class Num_217 {public static void main(String[] args) throws NumberFormatException, IOException{BufferedReader in = new BufferedReader(new InputStreamReader(System.in));int t=Integer.parseInt(in.readLine());while(t-->0){String[] input=in.readLine().split(" ");int letter=input[0].charAt(0);int number=Integer.parseInt(input[1]);if(letter>=97 && letter<=122)System.out.println(number-letter+96);elseSystem.out.println(number+letter-64);}}}