LeetCode-Easy-Java-Longest Continuous Increasing Subsequence

找到一个数组中连续增长的最大长度

题目描述：

Given an unsorted array of integers, find the length of longest continuous increasing subsequence.

Example 1:

Input: [1,3,5,4,7]Output: 3Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4. 

Example 2:

Input: [2,2,2,2,2]Output: 1Explanation: The longest continuous increasing subsequence is [2], its length is 1. 

Note: Length of the array will not exceed 10,000.

解决思路：

！！！首先一定要先判断是否为空，空则返回0；

然后从第一位循环判断是否当前数比下一个数小，如果小则长度+1；

如果大于或等于则重置长度值，重新计算；（！！！等于也不属于递增情况）

结果值最终取得最大的长度值。

class Solution {    public int findLengthOfLCIS(int[] nums) {        if(nums.length==0){            return 0;        }        int result=1;        int len=1;        for(int i=0;i<nums.length-1;i++){            if(nums[i]<nums[i+1]){                len=len+1;            }else{                len=1;            }            if(result<len){                    result=len;                }        }                 return result;    }}

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