HDU 6216 A Cubic number and A Cubic Number

A Cubic number and A Cubic Number

Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 65535/32768 K (Java/Others)
Total Submission(s): 160 Accepted Submission(s): 99

Problem Description
A cubic number is the result of using a whole number in a multiplication three times. For example, 3×3×3=27 so 27 is a cubic number. The first few cubic numbers are 1,8,27,64 and 125. Given an prime number p. Check that if p is a difference of two cubic numbers.

Input
The first of input contains an integer T (1≤T≤100) which is the total number of test cases.
For each test case, a line contains a prime number p (2≤p≤1012).

Output
For each test case, output ‘YES’ if given p is a difference of two cubic numbers, or ‘NO’ if not.

Sample Input
10
2
3
5
7
11
13
17
19
23
29

Sample Output
NO
NO
NO
YES
NO
NO
NO
YES
NO
NO

Source
2017 ACM/ICPC Asia Regional Qingdao Online

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题意：
给一个质数，问是否为两个立方数的差。

思路：
青岛网络赛的签到题，我可能是活在梦里吧。
Cuban Prime:只有相邻两个立方数的差可能为质数。
由于题目给的一定是质数，所以只要打相邻立方数的差的表就行了……
我今天都干了些啥啊……

代码：

#include<bits/stdc++.h>#define maxn 1000000#define ll long longusing namespace std;ll ans[maxn];void init(){    ll i,cnt=0;    for(i=2;i<maxn;i++)    {        ans[cnt++]=i*i*i-(i-1)*(i-1)*(i-1);    }}int main(){    init();    int t;    scanf("%d",&t);    while(t--)    {        ll p;        scanf("%lld",&p);        int i;        int flag=0;        for(i=0;i<999997;i++)        {            if(p==ans[i])            {                flag=1;                break;            }            if(p<ans[i]) break;        }        if(flag) printf("YES\n");        else printf("NO\n");    }}