HDU-2017 ACM/ICPC Asia Regional Qingdao Online-1003-The Dominator of Strings
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ACM模版
描述
题解
理论上直接
代码
#include <cstdio>#include <cstring>#include <string>#include <iostream>#include <algorithm>using namespace std;const int MAXN = 1e5 + 10;int n;char s[MAXN];string ss[MAXN];int main(){ int T; scanf("%d", &T); while (T--) { scanf("%d", &n); int tag = 0; for (int i = 0; i < n; i++) { scanf("%s", s); ss[i] = s; if (ss[i].length() > ss[tag].length()) { tag = i; } } bool flag = true; for (int i = 0; i < n; i++) { if (i != tag) { if (ss[tag].find(ss[i], 0) == string::npos) { flag = false; break; } } } if (flag) { printf("%s\n", ss[tag].c_str()); } else { printf("No\n"); } } return 0;}
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