【UVA 548 Tree】二叉树构造 & 遍历
来源:互联网 发布:录像配音软件 编辑:程序博客网 时间:2024/06/03 15:56
You are to determine the value of the leaf node in a given binary tree that is the terminal node of a
path of least value from the root of the binary tree to any leaf. The value of a path is the sum of values
of nodes along that path.
Input
The input file will contain a description of the binary tree given as the inorder and postorder traversal
sequences of that tree. Your program will read two line (until end of file) from the input file. The first
line will contain the sequence of values associated with an inorder traversal of the tree and the second
line will contain the sequence of values associated with a postorder traversal of the tree. All values
will be different, greater than zero and less than 10000. You may assume that no binary tree will have
more than 10000 nodes or less than 1 node.
Output
For each tree description you should output the value of the leaf node of a path of least value. In the
case of multiple paths of least value you should pick the one with the least value on the terminal node.
Sample Input
3 2 1 4 5 7 6
3 1 2 5 6 7 4
7 8 11 3 5 16 12 18
8 3 11 7 16 18 12 5
255
255
Sample Output
1
3
255
题意: 根据中序遍历和后序遍历构造二叉树,并输出从根遍历权值最小的轮径的叶子节点,权值相同的情况下,输出叶子节点最小的那个
思路 : 构造 & 遍历
AC代码:
#include<cstdio>#include<cmath>#include<deque>#include<queue>#include<vector>#include<cstring>#include<algorithm>using namespace std;const int MAX = 1e5 + 10;const int INF = 1e9 + 7;typedef long long LL;int l[MAX],r[MAX],h[MAX],z[MAX],nl,ans,sum;char c;bool readz(){ char c; nl = 1; if(scanf("%d",&z[1]) == -1) return 0; while(scanf("%c",&c) && c == ' ') scanf("%d",&z[++nl]); return 1;}void readh(){ for(int i = 1; i <= nl; i++) scanf("%d",&h[i]);}int gz(int l1,int r1,int l2,int r2){ if(l1 > r1) return 0; int t = h[r2]; int n = l1; while(z[n] != t) n++; int nn = n - l1; l[t] = gz(l1,n - 1,l2,l2 + nn - 1); r[t] = gz(n + 1,r1,l2 + nn,r2 - 1); return t;}void sc(int o,int vl){ vl += o; if(!l[o] && !r[o]){ if(vl < ans || (vl == ans && o < sum)){ ans = vl; sum = o; return ; } } if(l[o]) sc(l[o],vl); if(r[o]) sc(r[o],vl);}int main(){ while(readz()){ readh(); memset(l,0,sizeof l); memset(r,0,sizeof r); gz(1,nl,1,nl); ans = sum = INF; sc(h[nl],0); printf("%d\n",sum); } return 0;}
- 【UVA 548 Tree】二叉树构造 & 遍历
- UVA 548 Tree(数据结构,二叉树,遍历)
- UVa 548 - Tree 二叉树的重建与遍历
- UVa 548 - Tree【二叉树的递归遍历(DFS)】
- uva 548 tree 二叉树的各种遍历
- Uva 248 Tree//二叉树遍历,递归
- 二叉树 UVA 548 Tree
- UVA - 548 Tree 二叉树
- UVa--548 Tree(二叉树)
- UVA 536 Tree Recovery (二叉树的遍历)
- UVA 548 Tree 中序+后序构造二叉树dfs
- 遍历构造二叉树
- UVa 548 - Tree 二叉树的重建——中序遍历与后续遍历进行建树
- UVA 548-Tree(二叉树)
- UVa 548 - Tree(二叉树)
- UVA 548Tree(二叉树建树)
- UVA 548(DFS)+二叉树遍历
- UVa 112 - Tree Summing 二叉树构造, 二叉树路径和
- SSH入门项目-4-功能完善之CRUD
- 字符串全排列
- GCC编译过程分解
- Linux 学习路程(3)文件权限
- 关于verilog几条语法
- 【UVA 548 Tree】二叉树构造 & 遍历
- 智能算法推荐到底是不是原罪
- 关于putchar与getchar
- Eclipse添加jdk
- 多项式加法
- 孤独真的能毁掉一个人吗?
- 归并排序
- javascript基本知识整理三
- java开发教程-excel文件的读写