大数取模

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这里记一下两种方法

1、字符串

#include <iostream>#include <cstdio>#include <cstring>using namespace std;typedef long long ll;int main(){    char num[100005];    int i, j, x;    while(~scanf("%s %d", num,&x)){       ll ans = 0;       for(i = 0; i < strlen(num); ++i){           ans = ans*10 + (num[i]-'0');           ans %= x;       }       printf("%lld\n",ans);       getchar();    }    return 0;}

1、JAVA（本人不擅长JAVA。。。选自大牛博客）

import java.io.*;import java.util.*;import java.math.BigInteger;public class Main{    public static void main(String args[])    {        BigInteger big1 = new BigInteger("0");BigInteger big2 = new BigInteger("0");Scanner cin = new Scanner (System.in);while(cin.hasNext()){big1 = cin.nextBigInteger();big2 = cin.nextBigInteger();big1 = big1.remainder(big2);System.out.println(big1);}    }}

JAVA代码原地址：http://m.blog.csdn.net/ysc504/article/details/8818279

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