模拟-Codeforces 777C

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C. Alyona and Spreadsheet
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output

During the lesson small girl Alyona works with one famous spreadsheet computer program and learns how to edit tables.

Now she has a table filled with integers. The table consists of n rows and m columns. By ai, j we will denote the integer located at the i-th row and the j-th column. We say that the table is sorted in non-decreasing order in the column j if ai, j ≤ ai + 1, j for all i from 1 to n - 1.

Teacher gave Alyona k tasks. For each of the tasks two integers l and r are given and Alyona has to answer the following question: if one keeps the rows from l to r inclusive and deletes all others, will the table be sorted in non-decreasing order in at least one column? Formally, does there exist such j that ai, j ≤ ai + 1, j for all i from l to r - 1 inclusive.

Alyona is too small to deal with this task and asks you to help!

Input

The first line of the input contains two positive integers n and m (1 ≤ n·m ≤ 100 000) — the number of rows and the number of columns in the table respectively. Note that your are given a constraint that bound the product of these two integers, i.e. the number of elements in the table.

Each of the following n lines contains m integers. The j-th integers in the i of these lines stands for ai, j (1 ≤ ai, j ≤ 109).

The next line of the input contains an integer k (1 ≤ k ≤ 100 000) — the number of task that teacher gave to Alyona.

The i-th of the next k lines contains two integers li and ri (1 ≤ li ≤ ri ≤ n).

Output

Print "Yes" to the i-th line of the output if the table consisting of rows from li to ri inclusive is sorted in non-decreasing order in at least one column. Otherwise, print "No".

Example
input
5 41 2 3 53 1 3 24 5 2 35 5 3 24 4 3 461 12 54 53 51 31 5
output
YesNoYesYesYesNo
Note

In the sample, the whole table is not sorted in any column. However, rows 1–3 are sorted in column 1, while rows 4–5 are sorted in column 3.



题意:给了你两个数代表两行,让你从所有列中找是否满足这两行之间的所有数非递减

思路:首先用vector存数据,然后直接暴力k次询问肯定会超时,我们记录一下每一行按非递减顺序能到达的最大位置,如果它们之间包含了给的两个数的范围就输出Yes,否则输出No

#include<cstdio>#include<cstring>#include<algorithm>#include<vector>using namespace std;const int N = 100010;vector<int>vec[N];int res[N];int main(){    int n,m;    scanf("%d%d",&n,&m);    for(int i = 0; i < n; i++)    {        for(int j = 0; j < m; j++)        {            int x;            scanf("%d",&x);            vec[i].push_back(x);        }    }    memset(res,0,sizeof(res));    for(int j = 0; j < m; j++)    {       for(int i = 0; i < n; )       {           int flag = i;           while(flag + 1 < n && vec[flag][j] <= vec[flag + 1][j])           {               flag++;           }           for(int k = i; k <= flag; k++)               res[k] = max(res[k],flag);           i = flag + 1;       }    }//        for(int i = 0; i < n; i++)//            printf("%d\n",res[i]);    int q;    scanf("%d",&q);    while(q--)    {        int l,r;        scanf("%d%d",&l,&r);        l--;        r--;        if(res[l] >= r)            printf("Yes\n");        else            printf("No\n");    }    return 0;}