[LeetCode]172. Factorial Trailing Zeroes
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题目描述:Given an integer n, return the number of trailing zeroes in n!.
分析:返回n!后面的尾0个数
解题思路:将n除以5后的结果累加
public int trailingZeroes(int n) { int result = 0; while(n>0){ n=n/5; result+=n; } return result; }
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