LeetCode.341 Flatten Nested List Iterator
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题目:
Given a nested list of integers, implement an iterator to flatten it.
Each element is either an integer, or a list -- whose elements may also be integers or other lists.
Example 1:
Given the list [[1,1],2,[1,1]]
,
By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1,1,2,1,1]
.
Example 2:
Given the list [1,[4,[6]]]
,
By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1,4,6]
.
分析:
/** * // This is the interface that allows for creating nested lists. * // You should not implement it, or speculate about its implementation * public interface NestedInteger { * * // @return true if this NestedInteger holds a single integer, rather than a nested list. * public boolean isInteger(); * * // @return the single integer that this NestedInteger holds, if it holds a single integer * // Return null if this NestedInteger holds a nested list * public Integer getInteger(); * * // @return the nested list that this NestedInteger holds, if it holds a nested list * // Return null if this NestedInteger holds a single integer * public List<NestedInteger> getList(); * } */public class NestedIterator implements Iterator<Integer> { //考虑到子集中还有集合,当遍历到子集为集合时,需要使用stack。然后递归 Stack<NestedInteger> stack; public NestedIterator(List<NestedInteger> nestedList) { stack=new Stack<NestedInteger>(); for(int i=nestedList.size()-1;i>=0;i--){ //倒序将整个子集放入 stack.push(nestedList.get(i)); } } @Override public Integer next() { //从stack中取出元素 return stack.pop().getInteger(); } @Override public boolean hasNext() { while(!stack.empty()){ NestedInteger cur=stack.peek(); if(cur.isInteger()){ return true; } //那么就是空串 stack.pop(); //不是空串的集合 for(int i=cur.getList().size()-1;i>=0;i--){ stack.push(cur.getList().get(i)); } } return false; }}/** * Your NestedIterator object will be instantiated and called as such: * NestedIterator i = new NestedIterator(nestedList); * while (i.hasNext()) v[f()] = i.next(); */
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