718. Maximum Length of Repeated Subarray
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原网址为https://leetcode.com/problems/maximum-length-of-repeated-subarray/description/
Given two integer arrays A
and B
, return the maximum length of an subarray that appears in both arrays.
Example 1:
Input:A: [1,2,3,2,1]B: [3,2,1,4,7]Output: 3Explanation: The repeated subarray with maximum length is [3, 2, 1].
Note:
- 1 <= len(A), len(B) <= 1000
- 0 <= A[i], B[i] < 100
代码:
class Solution {public: int findLength(vector<int>& A, vector<int>& B) { int m = A.size() + 1; int n = B.size() + 1; int max = 0; vector<vector<int>> maxLenPostfix(m); for (int i = 0; i < m; i++) maxLenPostfix[i].resize(n, 0); for (int i = 1; i < m; i++) { for (int j = 1; j < n; j++) { if (A[i - 1] == B[j - 1]) { maxLenPostfix[i][j] = maxLenPostfix[i - 1][j - 1] + 1; if (maxLenPostfix[i][j] > max) max = maxLenPostfix[i][j]; } else maxLenPostfix[i][j] = 0; } } return max; }};
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