C语言实现扫雷程序

来源：互联网发布：劳动收入份额数据编辑：程序博客网时间：2024/05/17 03:27

Mine_Clear.h

#ifndef _MINE_CLEAR_H_#include<stdio.h>#include<stdlib.h>#include<windows.h>#include<time.h>#define _MINE_CLEAR_H_#define ROW 9int get_num(char mines[][ROW], int x, int y);void expend(int x,int y,char mines[][ROW],char block[][ROW]);void openOne(int x,int y,char mines[][ROW],char block[][ROW]);void printblock(char mines[][ROW],char block[][ROW]);void init(char mines[ROW][ROW], char block[ROW][ROW], int n);int is_T_F(char block[][ROW],char mines[][ROW]);int run(char block[][ROW],char mines[][ROW]);#endif

Mine_Clear.c

#include"Mine_Clear.h"int get_num(char mines[][ROW], int x, int y){      int count = 0;      if (mines[x - 1][y - 1] == '1' && x-1>= 0 && x-1<ROW && y-1>=0 && y-1<ROW )//左上方      {          count++;      }      if (mines[x - 1][y] == '1' && x-1>= 0 && x-1<ROW && y>=0 && y<ROW)//左边      {          count++;     }      if (mines[x - 1][y + 1] == '1' && x-1>= 0 && x-1<ROW && y+1>=0 && y+1<ROW)//左下方      {          count++;      }      if (mines[x][y - 1] == '1' && x>= 0 && x<ROW && y-1>=0 && y-1<ROW)//上方      {          count++;      }      if (mines[x][y + 1] == '1' && x>= 0 && x<ROW && y+1>=0 && y+1<ROW)//下方      {          count++;      }    if (mines[x + 1][y - 1] == '1' && x+1>= 0 && x+1<ROW && y-1>=0 && y-1<ROW)//右上方      {        count++;      }    if (mines[x + 1][y] == '1' && x+1>= 0 && x+1<ROW && y>=0 && y<ROW)//右方      {        count++;      }    if (mines[x + 1][y + 1] == '1' && x+1>= 0 && x+1<ROW && y+1>=0 && y+1<ROW)//右下方      {        count++;      }    return  count;  }  void expend(int x,int y,char mines[][ROW],char block[][ROW]){if(block[x][y]=='*'&&mines[x][y]!=1){if(get_num(mines, x, y)==0){block[x][y]='0';if(x-1>=0 && x-1<ROW && y-1>=0 && y-1<ROW) {expend(x-1,y-1,mines,block);}if(x-1>=0&&x-1<ROW&&y>=0&&y<ROW){expend(x-1,y,mines,block);}if(x-1>=0&&x-1<ROW&&y+1>=0&&y+1<ROW){expend(x-1,y+1,mines,block);}if(x>=0&&x<ROW&&y-1>=0&&y-1<ROW){expend(x,y-1,mines,block);}if(x>=0&&x<ROW&&y+1>=0&&y+1<ROW){expend(x,y+1,mines,block);}if(x+1>=0&&x+1<ROW&&y-1>=0&&y-1<ROW){expend(x+1,y-1,mines,block);}if(x+1>=0&&x+1<ROW&&y>=0&&y<ROW){expend(x+1,y,mines,block);}if(x+1>=0&&x+1<ROW&&y+1>=0&&y+1<ROW){expend(x+1,y+1,mines,block);}}else if(get_num(mines, x, y)!=0){block[x][y]=('0'+get_num(mines, x, y));}}}void openOne(int x,int y,char mines[][ROW],char block[][ROW]){if(x>=0&&y>=0&&x<=ROW-1&&y<=ROW-1){if(mines[x][y]=='1'){block[x][y]='X';}else{expend(x,y,mines,block);}}}void printblock(char mines[][ROW],char block[][ROW]){int i,j;printf(" 0   ");for(i=1;i<=ROW;i++){printf("%d ",i);}printf("\n    ");for(i=1;i<=2*ROW;i++){printf("-");}printf("\n");for(i=0;i<ROW;i++){printf(" %d | ",i+1);for(j=0;j<ROW;j++){printf("%c ",block[i][j]);}printf("\n");}printf("\n\n");}void init(char mines[ROW][ROW], char block[ROW][ROW], int n){int i,j;srand((unsigned int)time(NULL)); for(i=0;i<n;i++){for(j=0;j<n;j++){mines[i][j]='0'+((double)rand()/RAND_MAX+0.15);block[i][j]='*';}}}int is_T_F(char block[][ROW],char mines[][ROW]){int i,j;for(i=0;i<ROW;i++){for(j=0;j<ROW;j++){if(block[i][j]=='*'&&mines[i][j]!='1'){return 0;}}}return 1;}int run(char block[][ROW],char mines[][ROW]){int x,y;init(mines,block,ROW);printblock(mines,block);printf("请输入一个坐标：");scanf("%d %d",&x,&y); x-=1;y-=1;while(mines[x][y]=='1'){init(mines,block,ROW);}system("cls");openOne(x,y,mines,block);printblock(mines,block);while(mines[x][y]!='1'){printf("请输入一个坐标：");scanf("%d %d",&x,&y); x-=1;y-=1;system("cls");openOne(x,y,mines,block);printblock(mines,block);if(0==is_T_F(block,mines)){continue;}else if(1==is_T_F(block,mines)){printf("赢了！\n");return 1;}}printf("输了！\n");return 0;}

main.c

#include"Mine_Clear.h"int main(){int flag=1;char mines[ROW][ROW];char block[ROW][ROW];while(flag) {run(block,mines);printf("还继续吗？  1.继续，  0.退出\n");scanf("%d",&flag);system("cls");}printf("谢谢使用\n");system("pause");return 0; }

鉴于这游戏太烧脑了，所以测试了简单难度的

阅读全文

0 0