杭电acmP1002A + B Problem II（大数初步运用）

A + B Problem II
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 392274 Accepted Submission(s): 75946

Problem Description
I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

Output
For each test case, you should output two lines. The first line is “Case #:”, # means the number of the test case. The second line is the an equation “A + B = Sum”, Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

Sample Input
2
1 2
112233445566778899 998877665544332211

Sample Output
Case 1:
1 + 2 = 3

Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110

这个方法没有ac import java.util.Scanner;public class P1002 {    public static void main(String[] args) {      Scanner sc=new Scanner(System.in);      while(sc.hasNext()){      int t=sc.nextInt();      long[][] a=new long[t][2];      long[] sum=new long[t];      for(int i=0;i<t;i++){            for(int j=0;j<2;j++){             a[i][j]=sc.nextLong();            }          }      for(int i=0;i<t;i++){          sum[i]+=a[i][0]+a[i][1];          }      for(int i=0;i<t;i++){          System.out.println("Case"+(i+1)+":");          System.out.println(a[i][0]+"+"+a[i][1]+"="+sum[i]);              System.out.println();         }      }    }}

大数初步运用

/*直接运用java中的BigDecimal方法，ac/import java.math.BigDecimal;import java.util.Scanner;public class P1002 {    public static void main(String[] args) {       Scanner sc=new Scanner(System.in);       while(sc.hasNext()){           int n=sc.nextInt();           int num=0;           for(int i=0;i<n;i++){              BigDecimal a=sc.nextBigDecimal();              BigDecimal b=sc.nextBigDecimal();              BigDecimal c=a.add(b);              num++;              System.out.println("Case "+num+":");              System.out.println(a.toString()+" + "+b.toString()+" = "+c.toString());              if(i<n-1){                  System.out.println();              }             }      }    }}