ZJU-1099

来源：互联网发布：java中线程同步的方法编辑：程序博客网时间：2024/06/06 04:45

果然是著名的无聊题，最后一行要换行，害我PE了两下才发现。
简单的模拟处理HTML

//2008-01-13 17:41:07 Accepted 1099 C++ 00:00.00 392K#include<stdio.h>#include<string.h>int main(){    freopen("1099.txt","r",stdin);    char word[30];    int count=0,tc;    while(scanf("%s",word)!=EOF)    {        tc = strlen(word);        if(word[0]=='<')        {            if(word[1]=='b')            {                printf("/n");                count=0;            }            if(word[1]=='h')            {                if(count!=0)                    printf("/n");                printf("--------------------------------------------------------------------------------/n");                count=0;            }        }        else        {            if(count+1+tc<=80)            {                if(count==0)                {                    printf("%s",word);                    count += tc;                }                else                {                    printf(" %s",word);                    count += 1+tc;                }            }            else            {                printf("/n%s",word);                count=tc;            }        }    }    printf("/n");    fclose(stdin);    return 0;}