zoj 1738 Lagrange's Four-Square Theorem
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/*zoj_1738 dp思路:状态方程dp[i][j]表示元素i分解成j个数的平方和的可能数*/#include <iostream>#include <cstdio>#include <string.h>#define N 40000using namespace std;int dp[N][5];int main(){ int n,i,j,k; memset( dp,0,sizeof(dp) ); dp[0][0]=1; for( i=1;i*i<N;i++ ) for( j=1;j<5;j++ ) for( k=i*i;k<N;k++ ) dp[k][j]+=dp[k-i*i][j-1]; while( cin>>n && n ) printf( "%d\n",dp[n][1]+dp[n][2]+dp[n][3]+dp[n][4] ); return 0;}
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