1218. 纪念邮票

注意i的范围和满足的条件

#include <iostream>#include <cmath>using namespace std;int main(){    int m,n,t;    cin>>n>>m;    for(int i=sqrt(2.0*n)+1;i>=1;i--)    {        t=m-i*(i-1)/2;        if(t%i==0&&t/i>0&&t/i+i-1<=n)            cout<<"["<<t/i<<","<<t/i+i-1<<"]"<<endl;    }    return 0;}