递归十化二

#include <iostream>using namespace std;void d2b(int n){if(n==0){cout<<"0";}else{d2b(n/2);cout<<n%2;}}int main() { int a;                                                          cout<<"请要转化的十进制数为:";    cin>>a;    cout<<"转换成为二进制数为:";    d2b(a);    cout<<endl;    return 0; }