poj2525 Mayor's posters
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线段树+离散化,
因为每个结点代表的不是一个点,而是一段,所以把每个线段的后端点+1,形成【x1,x2)的半开半闭区间,。。。。
code
#include <set>#include <map>#include <ctime>#include <queue>#include <cmath>#include <stack>#include <limits>#include <vector>#include <bitset>#include <string>#include <cstdio>#include <cstring>#include <fstream>#include <string.h>#include <iostream>#include <algorithm>#define Si set<int>#define LL long long#define pb push_back#define PS printf(" ")#define Vi vector<int>#define LN printf("\n")#define lson l,m,rt << 1#define rson m+1,r,rt<<1|1#define SD(a) scanf("%d",&a)#define PD(a) printf("%d",a)#define SET(a,b) memset(a,b,sizeof(a))#define FF(i,a) for(int i(0);i<(a);i++)#define FD(i,a) for(int i(a);i>=(1);i--)#define FOR(i,a,b) for(int i(a);i<=(b);i++)#define FOD(i,a,b) for(int i(a);i>=(b);i--)#define readf freopen("input.txt","r",stdin)#define writef freopen("output.txt","w",stdout)const int maxn = 50001;const long long BigP=999983;const int INF = 0x3fffffff;const int dx[]={0,1,0,-1};const int dy[]={1,0,-1,0};const double pi = acos(-1.0);const double eps= 1e-7;using namespace std;int N,M,cnt,ans1;int reg[maxn][2];int X[maxn<<2];int col[maxn<<2];bool hash[maxn];void PushDown(int rt){ if(col[rt]){ col[rt<<1]=col[rt<<1|1]=col[rt]; col[rt]=0; }}void update(int L,int R,int c,int l,int r,int rt){ if(L<=l && R>=r){ col[rt]=c; return; } PushDown(rt); int m=(l+r)>>1; if(L<=m) update(L,R,c,lson); if(R>m) update(L,R,c,rson);}int BinSearch(int key){ int l=0,r=cnt; while(l<=r){ int m=(l+r)/2; if(X[m]==key) return m; else if(X[m]<key){ l=m+1; }else{ r=m-1; } } return -1;}void query(int l,int r,int rt) {if (col[rt]) { //puts("!!!!!!");if (!hash[col[rt]]) ans1++;hash[ col[rt] ] = true;return ;}if (l == r) return ;int m = (l + r) >> 1;query(lson);query(rson);}void print(int l,int r,int rt){ printf("l:%d r:%d col[rt]%d\n",l,r,col[rt]); if(l==r) return ; int m=(l+r)>>1; print(lson); print(rson);}int main(){ int cas; SD(cas); while(cas--){ SET(col,0); SET(hash,0); int tcnt=0; SD(M); FOR(i,1,M){ SD(reg[i][0]); SD(reg[i][1]); reg[i][1]++; X[tcnt++]=reg[i][0]; X[tcnt++]=reg[i][1]; } sort(X,X+tcnt); cnt=0; FOR(i,1,tcnt-1){ if(X[i]!=X[i-1]) X[++cnt]=X[i]; } FOR(i,1,M){ int L=BinSearch(reg[i][0]); int R=BinSearch(reg[i][1]); update(L,R-1,i,0,cnt,1); } //print(0,cnt,1); ans1=0; query(0,cnt,1); PD(ans1);LN; } return 0;}
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