hdu 3006 The Number of set

来源:互联网 发布:传奇霸业魔符进阶数据 编辑:程序博客网 时间:2024/05/22 08:57

The Number of set

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 832    Accepted Submission(s): 511


Problem Description
Given you n sets.All positive integers in sets are not less than 1 and not greater than m.If use these sets to combinate the new set,how many different new set you can get.The given sets can not be broken.
 

Input
There are several cases.For each case,the first line contains two positive integer n and m(1<=n<=100,1<=m<=14).Then the following n lines describe the n sets.These lines each contains k+1 positive integer,the first which is k,then k integers are given. The input is end by EOF.
 

Output
For each case,the output contain only one integer,the number of the different sets you get.
 

Sample Input
4 41 11 21 31 42 43 1 2 34 1 2 3 4
 

Sample Output
152
 

Source
2009 Multi-University Training Contest 11 - Host by HRBEU
 

Recommend
gaojie
 


位运算....

#include <stdio.h>#include <string.h>int s[1<<15];int main(){    int m,n,t,data;    while(scanf("%d%d",&n,&m)!=EOF)    {        memset(s,0,sizeof(s));        while(n--)        {            int ans=0;            scanf("%d",&t);            for(int i=1;i<=t;i++)            {                scanf("%d",&data);                ans=ans|(1<<(data-1));            }            s[ans]=1;            for(int i=0;i<=(1<<14);i++)            {                if(s[i])                s[ans|i]=1;            }        }        int num=0;        for(int i=0;i<(1<<14);i++)        if(s[i])        num++;        printf("%d\n",num);    }    return 0;}


原创粉丝点击