USACO Section 1.1.1 Your Ride Is Here
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简单题目,分别将两个字符窜中的字母通过asic码转换为数字,带权加和就可以了,别看简单,但是也有陷阱!
首先,作为乘法运算,结果对47取余,自然不会溢出,但是中间结果还是有可能溢出的,多以要注意对中间结果进行取余处理!
/*ID: zhuihun1PROG: rideLANG: C++*/#include <iostream>#include <fstream>#include <string.h>#include <stdio.h>#include<algorithm>#define MAXSIZE 5005using namespace std;ofstream fout ("ride.out");ifstream fin ("ride.in");int main(){ string str1,str2; int m,n,i,t; while(fin>>str1>>str2) { m=1;n=1; for(i=0;i<(int)str1.length();i++) { t=(str1[i]-64)%47; m*=t; m%=47; } for(i=0;i<(int)str2.length();i++) { t=(str2[i]-64)%47; n*=t; n%=47; } if(m%47==n%47) fout<<"GO"<<endl; else fout<<"STAY"<<endl; } return 0;}
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