longge's problem

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#include <iostream>

#include <stdio.h>

#include <math.h>

using namespace std;


__int64 cal(__int64 m)

{

__int64 i=m,k=sqrt(m),flag=m;

for(i=2;i<=k+1;i++) {

if(m%i==0)

flag=flag/i*(i-1);

while(m%i==0)

m/=i;

}

if(m!=1)

flag=flag/m*(m-1);

return flag;

}


int main()

{

__int64 n;

while(~scanf("%I64d",&n)) {

__int64 i=n,k=(__int64)sqrt(n),ans=n,sum=0,m=n;

for(i=2;i<=k;i++) {

if(n%i==0) {

sum+=cal(n/i)*i;

if(i*i!=n)

sum+=cal(n/(n/i))*(n/i);

}

if(m%i==0)

ans=ans/i*(i-1);

while(m%i==0)

m/=i;

}

if(m!=1)

ans=ans/m*(m-1);

printf("%I64d\n",ans+sum+n);

}

return 0;

}

/*

 Description

 Longge is good at mathematics and he likes to think about hard mathematical problems which will be solved by some graceful algorithms. Now a problem comes: Given an integer N(1 < N < 2^31),you are to calculate ∑gcd(i, N) 1<=i <=N. 

 

 "Oh, I know, I know!" Longge shouts! But do you know? Please solve it. 

 Input

 Input contain several test case. 

 A number N per line. 

 Output

 For each N, output ,∑gcd(i, N) 1<=i <=N, a line

 Sample Input

 2

 6

 Sample Output

 3

 15

*/