UVa:10673 Play with Floor and Ceil

数学水题，列一个方程，直接暴力即可。

#include <iostream>#include <cstdio>#include <cstring>#include <algorithm>#include <cmath>#define MAXN 100000000#define ll long longusing namespace std;int main(){    int T;    scanf("%d",&T);    while(T--)    {        ll x,k;        scanf("%lld%lld",&x,&k);        ll a=(int)floor(x*1.0/k),b=(int)ceil(x*1.0/k);        ll xx,yy;        for(int i=0; i<=MAXN; ++i)            if((x-i*a)%b==0)            {                xx=i;                yy=(x-i*a)/b;                break;            }        printf("%lld %lld\n",xx,yy);    }    return 0;}