打印十字图

问题描述

小明为某机构设计了一个十字型的徽标（并非红十字会啊），如下所示：

..$$$$$$$$$$$$$..
..$...........$..
$$$.$$$$$$$$$.$$$

$...$.......$...$
$.$$$.$$$$$.$$$.$
$.$...$...$...$.$
$.$.$$$.$.$$$.$.$
$.$.$...$...$.$.$
$.$.$.$$$$$.$.$.$
$.$.$...$...$.$.$
$.$.$$$.$.$$$.$.$
$.$...$...$...$.$
$.$$$.$$$$$.$$$.$
$...$.......$...$
$$$.$$$$$$$$$.$$$
..$...........$..
..$$$$$$$$$$$$$..

对方同时也需要在电脑dos窗口中以字符的形式输出该标志，并能任意控制层数。

输入格式

一个正整数 n (n<30) 表示要求打印图形的层数。

输出格式

对应包围层数的该标志。

样例输入1

1

样例输出1

..$$$$$..
..$...$..
$$$.$.$$$
$...$...$
$.$$$$$.$
$...$...$
$$$.$.$$$
..$...$..
..$$$$$..

样例输入2

3

样例输出2

..$$$$$$$$$$$$$..
..$...........$..
$$$.$$$$$$$$$.$$$
$...$.......$...$
$.$$$.$$$$$.$$$.$
$.$...$...$...$.$
$.$.$$$.$.$$$.$.$
$.$.$...$...$.$.$
$.$.$.$$$$$.$.$.$
$.$.$...$...$.$.$
$.$.$$$.$.$$$.$.$
$.$...$...$...$.$
$.$$$.$$$$$.$$$.$
$...$.......$...$
$$$.$$$$$$$$$.$$$
..$...........$..
..$$$$$$$$$$$$$.. 

import java.util.Scanner;public class Main{public static void main(String[] args) {Scanner asd = new Scanner(System.in);int n = asd.nextInt();char[][] b = new char[5][9];for (int i = 0; i < b.length; i++)for (int j = 0; j < b[i].length; j++)b[i][j] = '.';for (int i = 2; i < 7; i++)b[0][i] = '$';for (int i = 0; i < 9; i++) {b[2][i] = '$';b[4][i] = '$';}b[2][3] = b[2][5] = b[4][1] = b[4][7] = '.';b[3][0] = b[3][4] = b[3][8] = b[1][2] = b[1][6] = '$';char[][] a = new char[2 * n + 3][4 * n + 5];for (int i = 2 * n - 2; i < 2 * n + 3; i++)for (int j = 2 * n - 2; j < 2 * n + 7; j++)a[i][j] = b[i - 2 * n + 2][j - 2 * n + 2];for (int k = 2; k <= n; k++) {int m = 2 * (n - k);int x = 2 * (n + k);for (int i = 2 * (n - k); i < x+5; i++) {a[m][i] = '$';a[m + 1][i] = '.';}a[m][m] = a[m][m + 1] = a[m][x + 4] = a[m][x + 3] = '.';a[m + 1][m + 2] = a[m + 1][x + 2] = '$';a[m + 2][m] = a[m + 2][m + 1] = a[m + 2][m + 2] = '$';a[m + 2][x + 2] = a[m + 2][x + 3] = a[m + 2][x + 4] = '$';for (int i = 0; i < 2 * k; i++) {a[m + i + 3][m] = a[m + i + 3][x + 4] = '$';a[m + i + 3][m + 1] = a[m + i + 3][x + 3] = '.';}}for (int i = 0; i < a.length; i++) {for (int j = 0; j < a[i].length; j++)System.out.print(a[i][j]);System.out.println();}for (int i = a.length - 2; i >= 0; i--) {for (int j = a[i].length - 1; j >= 0; j--)System.out.print(a[i][j]);System.out.println();}}}