正整数的汉语读法

来源：互联网发布：写一个数组编辑：程序博客网时间：2024/04/30 15:32

题目描述：现在让你在普通的计算器（位数最多12位）上增加一个功能button，点击这个button之后能进行数字显示模式的切换，即能显示我们汉语对数字表达的习惯。比如计算器最初显示“零”，你按“1”这个按键之后，屏幕显示的是“一”，继续按”9”这个键，显示的是”十九”，继续按“0”这个键，显示的是“一百九十”… …而且，还要增加两个功能button，“退格键”和“清空键”。继续按退格键，显示的是“十九”，继续按“清空建”，显示的是“零”。

正确代码置顶：

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如果位数很大，兆以上的单位可以用getBase函数来获得，那么代码可以这么写：

1. 分段，如果不存在0，在len-i ==5 , == 9, == 13的位置输出万，亿，兆，其他位置输出数字+十百千即可

2. 如果存在0，遍历这段连续的0，如果中间经历len-i == 13, 9, 5的位置，输出相应的第一个单位兆>亿>万，之后break

·这里得强调一下： 当前一个非0输出一个base后，这个时候连续4个0是不用被输出的！！！！所以有了(k-i)%4 != 3

3. 如果0是末位，中间不用加0，否则要加一个0

#include <stdio.h>#include <string>#include <string.h>#include <iostream>using namespace std;string getBase(int num) {  if (num == 5)    return "万";  else if (num == 9)    return "亿";  else if (num == 13)    return "兆";  else    return "";}Another version:int main() {  string input = "101030100105";  string res = "";  string num[] = {"零","一","二","三","四","五","六","七","八","九"};  string unit[] = {"千","","十","百"};  int len = input.length(), i, j;  for (i = 0; i < len; ) {    if (input[i] != '0') {      res += num[input[i]-'0'];      res += unit[(len-i)%4];      res += getBase(len-i);      ++i;    }    else {      int j = i;      while (j < len && input[j] == '0')        ++j;           for (int k = i; k < j; ++k)        if (getBase(len-k) != "" && (k-i)%4 != 3) {          res += getBase(len-k);          break;        }      if (j != len)        res += "零";      i = j;    }  }  return 0;}

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注意连续的0的位置即可：

#include <stdio.h>#include <string>#include <iostream>using namespace std;string print(const string& num) {  string str[] = {"零","一","二","三","四","五","六","七","八","九","十","百","千"};  string unit[] = {"十","百","千"};  string res = "";  int i, j, len = num.length();  for (i = 0; i < len; ++i) {    if (num[i] == '0') {      for (j = i + 1; num[j] == '0' && j < len; ++j);      if (len - (i - 1) >= 6 && len - j <= 4)        res += "万";      if (j != len)        res += "零";      i = j - 1;      continue;    }    else {      res += str[num[i] - '0'];      //cout << (len - i) % 5 << endl;      // 2 3 4  6 7 8      if ((len - i) % 4 != 1)        res += unit[(len - i - 2) % 4];    }    if (len - i == 5)      res += "万";    if (len - i == 9)      res += "亿";  }  return res;}int main() {  string s = "1010";  cout << print(s) <<endl;  return 0;}

如果位数很大，兆以上的单位可以用getBase函数来获得，那么代码可以这么写：

1. 分段，如果不存在0，在len-i ==5 , == 9, == 13的位置输出万，亿，兆，其他位置输出数字+十百千即可

2. 如果存在0，遍历这段连续的0，如果中间经历len-i == 13, 9, 5的位置，输出相应的第一个单位兆>亿>万，之后break

3. 如果0是末位，中间不用加0，否则要加一个0

把握这三点即可。。。

#include <stdio.h>#include <string>#include <iostream>using namespace std;string getBase(int i) {  if (i == 5)    return "万";  else if (i == 9)    return "亿";  else if (i == 13)    return "兆";  else    return "";}string print(const string& num) {  string str[] = {"零","一","二","三","四","五","六","七","八","九"};  string unit[] = {"十","百","千"};  string res = "";  int i, j, len = num.length();  for (i = 0; i < len; ++i) {    if (num[i] == '0') {      for (j = i + 1; num[j] == '0' && j < len; ++j);            for (int k = len - i; k >= len - j; --k) {        string tmp = getBase(k);        if (tmp != "") {          res += tmp;          break;        }      }      if (j != len)        res += "零";      i = j - 1;      continue;    }    else {      res += str[num[i] - '0'];      //cout << (len - i) % 5 << endl;      // 2 3 4  6 7 8      if ((len - i) % 4 != 1)        res += unit[(len - i - 2) % 4];    }    res += getBase(len - i);  }  return res;}int main() {  string s = "101030100105";  cout << print(s) <<endl;  return 0;}

#include <stdio.h>#include <string>#include <string.h>#include <iostream>using namespace std;string getBase(int num) {  if (num == 5)    return "万";  else if (num == 9)    return "亿";  else if (num == 13)    return "兆";  else    return "";}Another version:int main() {  string input = "101030100105";  string res = "";  string num[] = {"零","一","二","三","四","五","六","七","八","九"};  string unit[] = {"千","","十","百"};  int len = input.length(), i, j;  for (i = 0; i < len; ) {    if (input[i] != '0') {      res += num[input[i]-'0'];      res += unit[(len-i)%4];      res += getBase(len-i);      ++i;    }    else {      int j = i;      while (j < len && input[j] == '0')        ++j;           for (int k = i; k < j; ++k)        if (getBase(len-k) != "" && (k-i)%4 != 3) {          res += getBase(len-k);          break;        }      if (j != len)        res += "零";      i = j;    }  }  return 0;}

#include <stdio.h>#include <string>#include <string.h>#include <iostream>using namespace std;string getBase(int num) {  if (num == 5)    return "万";  else if (num == 9)    return "亿";  else if (num == 13)    return "兆";  else    return "";}Another version:int main() {  string input = "101030100105";  string res = "";  string num[] = {"零","一","二","三","四","五","六","七","八","九"};  string unit[] = {"千","","十","百"};  int len = input.length(), i, j;  for (i = 0; i < len; ) {    if (input[i] != '0') {      res += num[input[i]-'0'];      res += unit[(len-i)%4];      res += getBase(len-i);      ++i;    }    else {      int j = i;      while (j < len && input[j] == '0')        ++j;           for (int k = i; k < j; ++k)        if (getBase(len-k) != "" && (k-i)%4 != 3) {          res += getBase(len-k);          break;        }      if (j != len)        res += "零";      i = j;    }  }  return 0;}

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