OCP 1Z0 051 148
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148. View the Exhibit and examine the structure of the PRODUCTS tables.
You want to generate a report that displays the average list price of product categories where the average
list price is less than half the maximum in each category.
Which query would give the correct output?
A. SELECT prod_category,avg(prod_list_price)
FROM products
GROUP BY prod_category
HAVING avg(prod_list_price) < ALL
(SELECT max(prod_list_price)/2
FROM products
GROUP BY prod_category);
B. SELECT prod_category,avg(prod_list_price)
FROM products
GROUP BY prod_category
HAVING avg(prod_list_price) > ANY
(SELECT max(prod_list_price)/2
FROM products
GROUP BY prod_category);
C. SELECT prod_category,avg(prod_list_price)
FROM products
HAVING avg(prod_list_price) < ALL
(SELECT max(prod_list_price)/2
FROM products
GROUP BY prod_category);
D. SELECT prod_category,avg(prod_list_price)
FROM products
GROUP BY prod_category
HAVING avg(prod_list_price) > ANY
(SELECT max(prod_list_price)/2
FROM products);
B D 两个>肯定是不对。
C 少了 group by 子句
Answer: A
You want to generate a report that displays the average list price of product categories where the average
list price is less than half the maximum in each category.
Which query would give the correct output?
A. SELECT prod_category,avg(prod_list_price)
FROM products
GROUP BY prod_category
HAVING avg(prod_list_price) < ALL
(SELECT max(prod_list_price)/2
FROM products
GROUP BY prod_category);
B. SELECT prod_category,avg(prod_list_price)
FROM products
GROUP BY prod_category
HAVING avg(prod_list_price) > ANY
(SELECT max(prod_list_price)/2
FROM products
GROUP BY prod_category);
C. SELECT prod_category,avg(prod_list_price)
FROM products
HAVING avg(prod_list_price) < ALL
(SELECT max(prod_list_price)/2
FROM products
GROUP BY prod_category);
D. SELECT prod_category,avg(prod_list_price)
FROM products
GROUP BY prod_category
HAVING avg(prod_list_price) > ANY
(SELECT max(prod_list_price)/2
FROM products);
B D 两个>肯定是不对。
C 少了 group by 子句
SQL> SELECT prod_category, AVG(prod_list_price) 2 FROM sh.products 3 HAVING AVG(prod_list_price) < ALL (SELECT MAX(prod_list_price) / 2 4 FROM sh.products 5 GROUP BY prod_category);SELECT prod_category, AVG(prod_list_price) FROM sh.productsHAVING AVG(prod_list_price) < ALL (SELECT MAX(prod_list_price) / 2 FROM sh.products GROUP BY prod_category)ORA-00937: not a single-group group function
SQL> SELECT prod_category, AVG(prod_list_price) 2 FROM sh.products 3 GROUP BY prod_category 4 HAVING AVG(prod_list_price) < ALL (SELECT MAX(prod_list_price) / 2 5 FROM sh.products 6 GROUP BY prod_category);PROD_CATEGORY AVG(PROD_LIST_PRICE)-------------------------------------------------- --------------------Software/Other 31.41307692307691 row selected
Answer: A
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