WERTYU题析

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Poj：http://poj.org/problem?id=2538

题析：

#include <stdio.h>int main(){     int i,c;     char *s = "1234567890-=qwertyuiop[]\asdfghjkl;'zxcvbnm,./";

     while( ( c = getchar ( ) ) == !EOF)                   //读入字符串

             for (i=1 ; s[i] && s[i]!=c ; i++)            //C中<span style="color: rgb(51, 51, 51); font-family: arial; font-size: 13px; line-height: 20.020000457763672px;">非>与>或，所以 s[i]  &&  s[i]!=c 而不是s[i]&&s[i]  != c</span>

<span style="color: rgb(51, 51, 51); font-family: arial; font-size: 13px; line-height: 20.020000457763672px;">                                                                                       //终止条件：s[i]</span>

<span style="color: rgb(51, 51, 51); font-family: arial; font-size: 13px; line-height: 20.020000457763672px;">                         if ( s[i] ) </span>

<span style="color: rgb(51, 51, 51); font-family: arial; font-size: 13px; line-height: 20.020000457763672px;">                               putchar ( s[i-1] );   </span>

<span style="color: rgb(51, 51, 51); font-family: arial; font-size: 13px; line-height: 20.020000457763672px;">                         else purchar(c);                                       //</span>

     return 0;}

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