HDU 1228 A + B 水水水

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Problem Description

读入两个小于100的正整数A和B,计算A+B.
需要注意的是:A和B的每一位数字由对应的英文单词给出.

Input

测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出.

Output

对每个测试用例输出1行,即A+B的值.

Sample Input

one + two =three four + five six =zero seven + eight nine =zero + zero =

Sample Output

39096
代码：
#include <iostream>  #include <cstdio>  #include <cstring>  using namespace std;  char s[10][10] = {"zero","one","two","three","four","five","six","seven","eight","nine"};  int  find (char ch[]){for(int i=0;i<10;i++){if(strcmp(s[i],ch)==0)break;}return i;}int main(){char q[10],w[10];int s1,s2;while(1){s1=s2=0;while(scanf("%s",q)&&strcmp(q,"+")==1){s1=s1*10+find(q);}while(scanf("%s",w)&&strcmp(w,"=")==1){s2=s2*10+find(w);}if(s1+s2==0)break;elsecout<<s1+s2<<endl;}return 0;}

多多练习对字符串的处理还是很有必要的。。

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