hdu 1130

大整数#include<stdio.h>int a[200][1000]={0};int main(){int i,j,k,len,t,n;   a[1][0]=1;len=1;  for(i=2;i<=100;i++)  {  for(j=0;j<len;j++)  a[i][j]=a[i-1][j]*(4*i-2);  for(k=j=0;j<len;j++)  {  a[i][j]+=k;  k=a[i][j]/10000;  a[i][j]%=10000;  }  while(k)  {  a[i][len++]=k%10000;  k=k/10000;  }  for(j=len-1;j>=0;j--)  {  t=a[i][j]%(i+1);  a[i][j-1]+=t*10000;  a[i][j]=a[i][j]/(i+1);  }//大数除法  }  while(scanf("%d",&n)!=EOF)  {  for(i=len-1;i>=0;i--)  if(a[n][i]!=0)  {  printf("%d",a[n][i]);  break;  }    for(j=i-1;j>=0;j--)printf("%04d",a[n][j]);  printf("\n");  }  return 0;}