[水]ZOJ2060

跟原来的fib一样只是把第0项第1项换成7和11

问是否能被三整除

打个表发现是4位一循环的规律

#include<bits/stdc++.h>using namespace std;int main(){    int n;    while(cin>>n)    {        if (n==0||n==1)            cout<<"no"<<endl;        if (n==2)            cout<<"yes"<<endl;        if (n>=3)        {            if((n-2)%4==0)                cout<<"yes"<<endl;            else                cout<<"no"<<endl;        }    }    return 0;}