1410132036-hd-Keep on Truckin'

Keep on Truckin'

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 8841    Accepted Submission(s): 6153

Problem Description

Boudreaux and Thibodeaux are on the road again . . .

"Boudreaux, we have to get this shipment of mudbugs to Baton Rouge by tonight!"

"Don't worry, Thibodeaux, I already checked ahead. There are three underpasses and our 18-wheeler will fit through all of them, so just keep that motor running!"

"We're not going to make it, I say!"

So, which is it: will there be a very messy accident on Interstate 10, or is Thibodeaux just letting the sound of his own wheels drive him crazy?

Input

Input to this problem will consist of a single data set. The data set will be formatted according to the following description.

The data set will consist of a single line containing 3 numbers, separated by single spaces. Each number represents the height of a single underpass in inches. Each number will be between 0 and 300 inclusive.

Output

There will be exactly one line of output. This line will be:

   NO CRASH

if the height of the 18-wheeler is less than the height of each of the underpasses, or:

   CRASH X

otherwise, where X is the height of the first underpass in the data set that the 18-wheeler is unable to go under (which means its height is less than or equal to the height of the 18-wheeler).
The height of the 18-wheeler is 168 inches.

Sample Input

180 160 170

Sample Output

CRASH 160

题目大意

      三个桥洞，货物高168，给出三个桥洞的高度，如果都可以通过就输出NO CRASH，如果x过不去，则输出CRASH X（x表示高度）。

代码

#include<stdio.h>int s[5];int main(){int a,b,c;int i,j;while(scanf("%d%d%d",&s[0],&s[1],&s[2])!=EOF){j=0;for(i=0;i<3;i++){if(s[i]<168)        break;    else        j++;}if(j==3)    printf("NO CRASH\n");else    printf("CRASH %d\n",s[i]);}return 0;}