HDU 1506 Largest Rectangle in a Histogram
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这个题一看就是求区间最小值。
因为直接做UVA 的时候 做过高效算法里面一个这样的题。 所以一下子就能想出思路。(UVA 1619 - Feel Good)
递推求一个数是一个区间最小值的 左端 和 右端。我也不知道为啥 不清空数组就会WA。。 明明感觉没什么影响啊。
#include <iostream>#include <cstdio>#include <cstdlib>#include <cstring>#include <string>#include <algorithm>#include <fstream>#include <set>#include <map>#include <queue>#include <stack>#include <list>#include <vector>#include <cmath>#include <iomanip>typedef long long LL;typedef unsigned long long LLU;const double PI=acos(-1.0);using namespace std;#define MAXN 100000+10LL a[MAXN];LL l[MAXN];LL r[MAXN];int main (){ LL n; while(scanf("%I64d",&n) && n){ memset(a,0,sizeof(a)); memset(r,0,sizeof(r)); memset(l,0,sizeof(l)); for(LL i = 1; i <= n; i++){ scanf("%I64d",&a[i]); l[i] = i; r[i] = i; } for(LL i = 1; i <= n; i++){ if(a[i] > 0){ while(a[l[i]-1] >= a[i]) l[i] = l[l[i] - 1]; } } for(LL i = n; i >= 1; i--){ if(a[i] > 0){ while(a[r[i]+1] >= a[i]) r[i] = r[r[i]+1]; } } LL M = 0; for(LL i = 1; i <= n; i++) M = max(M, (r[i]-l[i]+1)*a[i]); printf("%I64d\n",M); } return 0;}
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- hdu 1506 Largest Rectangle in a Histogram
- HDU 1506 Largest Rectangle in a Histogram
- hdu 1506 Largest Rectangle in a Histogram
- hdu 1506 Largest Rectangle in a Histogram
- hdu 1506 Largest Rectangle in a Histogram
- HDU 1506 Largest Rectangle in a Histogram
- hdu 1506 Largest Rectangle in a Histogram
- HDU 1506 Largest Rectangle in a Histogram
- hdu 1506 Largest Rectangle in a Histogram
- hdu 1506 Largest Rectangle in a Histogram
- HDU 1506 Largest Rectangle in a Histogram
- HDU 1506 Largest Rectangle in a Histogram
- hdu 1506 Largest Rectangle in a Histogram
- HDU 1506 Largest Rectangle in a Histogram
- HDU 1506 Largest Rectangle in a Histogram
- hdu 1506 Largest Rectangle in a Histogram
- hdu 1506 Largest Rectangle in a Histogram
- hdu 1506 Largest Rectangle in a Histogram
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