Single Number
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思路:数字均为成对出现,只有一个是光棍,因此想到了按位异或,成对出现的异或后为0,最终亦或结果即为所求
public class Solution { public int singleNumber(int[] A) { int single=0;for(int i=0;i<A.length;i++)single^=A[i];return single; }}
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