求最大子序列的实现

来源:互联网 发布:游戏角色设计软件 编辑:程序博客网 时间:2024/06/05 08:12


求最大子序列 C 源码的实现

先看原题

Maximum Subsequence Sum

Given a sequence of K integers { N1, N2, ..., NK }. A continuous subsequence is defined to be { Ni, Ni+1, ..., Nj } where 1 <= i <= j <= K. TheMaximum Subsequence is the continuous subsequence which has the largest sum of its elements. For example, given sequence { -2, 11, -4, 13, -5, -2 }, its maximum subsequence is { 11, -4, 13 } with the largest sum being 20.

Now you are supposed to find the largest sum, together with the first and the last numbers of the maximum subsequence.

Input Specification:

Each input file contains one test case. Each case occupies two lines. The first line contains a positive integer K (<= 10000). The second line contains K numbers, separated by a space.

Output Specification:

For each test case, output in one line the largest sum, together with the first and the last numbers of the maximum subsequence. The numbers must be separated by one space, but there must be no extra space at the end of a line. In case that the maximum subsequence is not unique, output the one with the smallest indices i and j (as shown by the sample case). If all the K numbers are negative, then its maximum sum is defined to be 0, and you are supposed to output the first and the last numbers of the whole sequence.

Sample Input:

10-10 1 2 3 4 -5 -23 3 7 -21

Sample Output:

10 1 4

http://www.patest.cn/contests/mooc-ds/01-2

C代码实现,基于在线处理算法,算法时间复杂度O(n)

#include <stdio.h>#include <stdlib.h>int MaxSubSum(int A[], int N, int* start, int* end){    int nMaxSum=-1, i=0,nThisSum=0,temp =0;    *start = A[0];    *end = A[N-1];    for( i =0; i<N; ++i)    {        nThisSum += A[i];        if(nThisSum < 0)        {            nThisSum = 0;            temp = i+1;        }        else if(nThisSum > nMaxSum)        {            nMaxSum = nThisSum;            *start = A[temp];            *end = A[i];        }    }    if(nMaxSum <0)        nMaxSum = 0;    return nMaxSum;}int main(){    int i;    int k;    scanf("%d",&k);    int *a = (int*)malloc(sizeof(int)*k);    for( i =0; i < k; ++i)    {        scanf("%d",&a[i]);    }    int start,end;    int ret = MaxSubSum(a, k, &start, &end);    printf("%d %d %d", ret, start, end);    free(a);    return 0;}


0 0
原创粉丝点击