Factorial Trailing Zeroes (java)
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题目:
Given an integer n, return the number of trailing zeroes in n!.
Note: Your solution should be in logarithmic time complexity.
java代码实现:
</pre><pre name="code" class="html">class Solution { public int trailingZeroes(int n) { int count = 0; for (long i=5; n/i>=1; i *= 5) //用int会有偏差 count += n/i; return count; }}
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