leetcode:数学:Factorial Trailing Zeroes(172)
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Given an integer n, return the number of trailing zeroes in n!.
Note: Your solution should be in logarithmic time complexity.
class Solution {public: int trailingZeroes(int n) { int ans = 0; while (n != 0) { ans += n / 5; n /= 5; } return ans; }};
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