[LeetCode] Compare Version Numbers

Compare two version numbers version1 and version1.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

class Solution {public:    int compareVersion(string version1, string version2) {        int v1 = 0,v2 = 0,idx1 = 0,idx2 = 0;        while(idx1 != version1.size() || idx2 != version2.size()){            v1 = 0;            while(idx1 != version1.size()){                if(version1[idx1] == '.'){                    idx1 ++;                    break;                }                v1 = 10 * v1 + (version1[idx1] - '0');                idx1 ++;            }            v2 = 0;            while(idx2 != version2.size()){                if(version2[idx2] == '.'){                    idx2 ++;                    break;                }                v2 = 10 * v2 + (version2[idx2] - '0');                idx2 ++;            }            if(v1 > v2) return 1;            if(v1 < v2) return -1;        }        return 0;    }};