[Leetcode]Unique binary search tree
来源:互联网 发布:手游网络加速 编辑:程序博客网 时间:2024/05/16 11:01
1. 没有元素,为1 count[0] = 1
2. 1个元素,为1 count[1] = 1
3. 2个元素,1为根加上2为根
count[2] = count[0] * count[1] + count[1] * count[0]
推理得到
count[3] = count[0] * count[2] + count[1] * count[1] + count[2] * count[0]
写的时候注意循环的条件。
0 0
- [LeetCode] Unique Binary Search Tree
- LeetCode : Unique Binary Search Tree
- 【LeetCode】Unique Binary Search Tree
- [Leetcode]Unique binary search tree
- Unique Binary Search Tree -- LeetCode
- Leetcode: Unique Binary Search Tree II
- LeetCode 96: Unique Binary Search Tree
- Leetcode - Tree /Dynamic Programming- Unique Binary Search
- Leetcode练习- Unique Binary Search Tree
- leetcode java unique binary search tree
- 【Leetcode】Unique Binary Search Tree II (DP)
- 【Leetcode】Unique Binary Search Tree in JAVA
- leetcode-unique binary search tree II
- Unique Binary Search Tree II -LeetCode
- [leetcode][tree] Unique Binary Search Trees
- [leetcode][tree] Unique Binary Search Trees II
- leetCode 96:Unique Binary Search Tree
- LeetCode #96 Unique Binary Search Tree
- EXCEL2007导入SQL生成新表并插入数据
- 外卖网站服务器端
- 实用的 jQuery下拉选择框插件集合
- 仿站 www.dapu.com
- 浏览器判断是否安装了ios/android客户端程序
- [Leetcode]Unique binary search tree
- quick-cocos2d-x 从2.2.5升级到3.3的体会
- android获取当前手机设备信息工具类
- ios enum typedef 枚举类型
- Struts2 Validation
- 好玩的造字程序
- setsockopt中参数之SO_REUSEADDR的意义(转)
- 解决eclipse闪退的办法
- HTML5最新经典俄罗斯方块游戏插件